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### has_greater

    template <class Lhs, class Rhs=Lhs, class Ret=dont_care>
    struct has_greater : public true_type-or-false_type {};

Inherits: If (i) `lhs` of type `Lhs` and `rhs` of type `Rhs` can be used in expression `lhs>rhs`, and (ii) `Ret=dont_care` or the result of expression `lhs>rhs` is convertible to `Ret` then inherits from true_type, otherwise inherits from false_type.

The default behaviour (`Ret=dont_care`) is to not check for the return value of binary `operator>`. If `Ret` is different from the default `dont_care` type, the return value is checked to be convertible to `Ret`. Convertible to `Ret` means that the return value of the operator can be used as argument to a function expecting `Ret`:

    void f(Ret);
    Lhs lhs;
    Rhs rhs;
    f(lhs>rhs); // is valid if has_greater<Lhs, Rhs, Ret>::value==true

If `Ret=void`, the return type is checked to be exactly `void`.

Header: `#include <boost/type_traits/has_greater.hpp>` or `#include <boost/type_traits/has_operator.hpp>` or `#include <boost/type_traits.hpp>`

Examples:

> `has_greater<Lhs, Rhs, Ret>::value_type` is the type `bool`.

> `has_greater<Lhs, Rhs, Ret>::value` is a `bool` integral constant expression.

> `has_greater<int>::value` is a `bool` integral constant expression that evaluates to `true`.

> `has_greater<long>` inherits from `true_type`.

> `has_greater<int, int, bool>` inherits from `true_type`.

> `has_greater<int, double, bool>` inherits from `true_type`.

> `has_greater<const int>` inherits from `true_type`.

> `has_greater<int*, int>` inherits from `false_type`.

> `has_greater<int*, double*>` inherits from `false_type`.

> `has_greater<int, int, std::string>` inherits from `false_type`.

See also: Operator Type Traits

Limitation:

- Requires a compiler with working SFINAE.

Known issues:

- This trait cannot detect whether binary `operator>` is public or not: if `operator>` is defined as a private member of `Lhs` then instantiating `has_greater<Lhs>` will produce a compiler error. For this reason `has_greater` cannot be used to determine whether a type has a public `operator>` or not.

      struct A { private: void operator>(const A&); };
      boost::has_greater<A>::value; // error: A::operator>(const A&) is private

- There is an issue if the operator exists only for type `A` and `B` is convertible to `A`. In this case, the compiler will report an ambiguous overload.

      struct A { };
      void operator>(const A&, const A&);
      struct B { operator A(); };
      boost::has_greater<A>::value; // this is fine
      boost::has_greater<B>::value; // error: ambiguous overload

- There is an issue when applying this trait to template classes. If `operator>` is defined but does not bind for a given template type, it is still detected by the trait which returns `true` instead of `false`. Example:

      #include <boost/type_traits/has_greater.hpp>
      #include <iostream>

      template <class T>
      struct contains { T data; };

      template <class T>
      bool operator>(const contains<T> &lhs, const contains<T> &rhs) {
      	return f(lhs.data, rhs.data);
      }

      class bad { };
      class good { };
      bool f(const good&, const good&) { }

      int main() {
      	std::cout<<std::boolalpha;
      	// works fine for contains<good>
      	std::cout<<boost::has_greater< contains< good > >::value<<'\n'; // true
      	contains<good> g;
      	g>g; // ok
      	// does not work for contains<bad>
      	std::cout<<boost::has_greater< contains< bad > >::value<<'\n'; // true, should be false
      	contains<bad> b;
      	b>b; // compile time error
      	return 0;
      }

- `volatile` qualifier is not properly handled and would lead to undefined behavior